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Question

Physics Question on Nuclear physics

The Binding energy per nucleon of 37Li^7_3Li and 24He^4_2He nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction 37Li+11H24He+24He+Q^7_3Li + ^1_1H \rightarrow ^4_2He + ^4_2He+Q, the value of energy Q released is:

A

-2.4MeV

B

8.4MeV

C

17.3MeV

D

19.6MeV

Answer

17.3MeV

Explanation

Solution

The correct option (C): 17.3MeV