Question
Question: The binding energy of deuteron <sub>1</sub>H<sup>2</sup> is 1.112 MeV per nucleon and a-particle <su...
The binding energy of deuteron 1H2 is 1.112 MeV per nucleon and a-particle 2He4 has a binding energy of 7.047 MeV per nucleon. Then in the relation :
1H2 + 1H2®2He4 + Q the energy Q released is :
A
1 MeV
B
11.9 MeV
C
23.8 MeV
D
931 MeV
Answer
23.8 MeV
Explanation
Solution
Released energy = BE of RHS – LHS
= (7.047 × 4) – (4 × 1.112)