Question

The binding energy of an electron in the ground state of the He atom is equal to 24eV. The energy required to remove both the electrons from the atom will be

• A. 59Ev
• B. 81eV
• C. 79eV
• D. None of these

Answer 1

Answer: (C)

79eV

Answer 2

Ionization energy of He $= \frac{Z^{2}}{n^{2}} \times 13.6$ $= \frac{2^{2}}{1^{2}} \times 13.6$

$= 54.4eV$

Energy required to remove both the electrons

$=$ binding energy + ionization energy

$=$ $24.6 + 54.4$ $=$ 79eV