Question

The battery of a trunk has an emp of 24 V. If the internal resistance of the battery is 0.8 $T_{1}$. What is the maximum current that can be drawn from the battery?

• A. 30 A
• B. 32 A
• C. 33 A
• D. 34 A

Answer 1

Answer: (A)

30 A

Answer 2

: Here, $\varepsilon = 24V$and $r = 0.8\Omega$

For the maximum current from the battery.

$\varepsilon = Ir$ ($\because R = 0$)

$\therefore I = \frac{\varepsilon}{r} = \frac{24}{0.8} = 30A$