Question

The average velocity of a freely falling body is numerically equal to half of the acceleration due to gravity. The velocity of the body as It reaches the ground is

• A. g
• B. $\frac{g}{2}$
• C. $\frac{g}{\sqrt{2}}$
• D. $\sqrt{2}g$

Answer 1

Answer: (A)

g

Answer 2

We have average velocity $=\frac{ g }{2}$ Since it is a free fall, average velocity, $v =\frac{ S }{ t }=\frac{\frac{1}{2} gt ^{2}}{ t }=\frac{ g }{2}$, where $t$ is the time