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Question: The average resisting force that must act on a 5 kg mass to reduce its speed from 65 cm/s to 15 cm/s...

The average resisting force that must act on a 5 kg mass to reduce its speed from 65 cm/s to 15 cm/s in 0.2s is

A

12.5 N

B

25 N

C

50 N

D

100 N

Answer

12.5 N

Explanation

Solution

F=m(vut)=5(6515)×1020.2=12.5NF = m\left( \frac{v - u}{t} \right) = \frac{5(65 - 15) \times 10^{- 2}}{0.2} = 12.5N