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Question: The average power required to lift a 100 kg mass through a height of 50 metres in approximately 50 s...

The average power required to lift a 100 kg mass through a height of 50 metres in approximately 50 seconds would be

A

50 J/s

B

5000 J/s

C

100 J/s

D

980 J/s

Answer

980 J/s

Explanation

Solution

P=mghtP = \frac { m g h } { t }=100×9.8×5050=980 J/s\frac { 100 \times 9.8 \times 50 } { 50 } = 980 \mathrm {~J} / \mathrm { s }