Question

The average power dissipated in a pure capacitance $AC$ circuit is

• A. $CV$
• B. zero
• C. $\frac{1}{CV^{2}}$
• D. $\frac{1}{4}CV^{2}$

Answer 1

Answer: (B)

zero

Answer 2

Average power in AC circuit is given by
$P=V_{r m s} I_{r m s} \cos \phi$
For pure capacitive circuit $\phi=90^{\circ}$
so $P=0 .$