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Question: The average molecular weight \(({M_n})\)of Teflon polymer is \(1,20,000\,g/mol\). Find the Degree of...

The average molecular weight (Mn)({M_n})of Teflon polymer is 1,20,000g/mol1,20,000\,g/mol. Find the Degree of polymerization.

Explanation

Solution

The degree of polymerization, or DP, is the number of monomeric units in a macromolecule or polymer or oligomer molecule. There is only one type of monomeric unit in a homopolymer. :

Formula used: Dpn=Xn=MnM0D{p_n} = {X_n} = \dfrac{{{M_n}}}{{{M_0}}}
Where MnM_n is the number-average molecular weight and M0M_0 is the molecular weight of the monomer unit.

Complete step by step solution:
Teflon is an important element used in non-stick cookware utensils. Teflon is made of a chemical compound named polytetrafluoroethylene (PTFE). Teflon is produced by tetrafluoroethylene undergoing free radical polymerization.
Here, the number of average molecular weight (Mn)({M_n}) of Teflon polymer == 1,20,0001,20,000g/mol
In Teflon, the monomer used is CF2CF2C{F_2} - C{F_2}.
So, the molecular weight of CF2CF2C{F_2} - C{F_2}is M0{M_0} =100 = 100g/mol
The equation used for the degree of polymerization:
\therefore DpnD{p_n} =Xn=MnM0 = {X_n} = \dfrac{{{M_n}}}{{{M_0}}}
Here, Mn{M_n} =1,20,000g/mol = 1,20,000\,g/mol and M0{M_0} =100g/mol = 100\,g/mol
Xn=1,20,000100{X_n} = \dfrac{{1,20,000}}{{100}}
=1200= 1200

Hence, the degree of polymerization of the Teflon is 12001200.

Note: Teflon is used as the coating for non-stick pans as Teflon is hydrophobic and has a high resistance capacity to heat. Because of high boiling point and a high melting point of Teflon, this chemical compound has fascinated scientists and students of science around the world. We can also find the degree of polymerization with the use of given equation for other polymers.