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Question

Chemistry Question on Ideal gas equation

The average kinetic energy of an ideal gas per molecule in SI unit at 25∘C25^{\circ} C will be

A

6.17×10−21kJ6.17 \times 10^{-21} kJ

B

6.17×10−21J6.17 \times 10^{-21} J

C

6.17×10−20J6.17 \times 10^{-20} J

D

7.16×10−20J7.16 \times 10^{-20} J

Answer

6.17×10−21J6.17 \times 10^{-21} J

Explanation

Solution

The average kinetic energy of an ideal gas per molecule in SI units at 25∘C25^{\circ} C will be 6.17×6.17 \times 10−21J10^{-21} J The average kinetic energy of an ideal gas per molecule is given by the expression Average kinetic energy =32kT=\frac{3}{2} kT Here, kk is boltzmann constant and TT is absolute temperature. k=1.36×10−23J/Kk =1.36 \times 10^{-23} J / K T=25+273=298 KT =25+273=298\, K Average kinetic energy =32×1.36×10−23J/K×298 K=\frac{3}{2} \times 1.36 \times 10^{-23} J / K \times 298\, K =6.17×10−21J=6.17 \times 10^{-21} J