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Question

Question: The average kinetic energy (in joules of) molecules in 8.0 g of methane at 27ŗ C is :...

The average kinetic energy (in joules of) molecules in 8.0 g of methane at 27ŗ C is :

A

6.21 × 10-20 J/molecule

B

6.21 × 10-21 J/molecule

C

6.21 × 10-22 J/molecule

D

3.1 × 10-22 J/molecule

Answer

6.21 × 10-21 J/molecule

Explanation

Solution

Average KE=32×8.314×3006.023×1023=6.21×1021/Jmolecule.KE = \frac{3}{2} \times \frac{8.314 \times 300}{6.023 \times 10^{23}} = 6.21 \times 10^{- 21}/Jmolecule..