Question

The average energy for molecules in one degree of freedom is–

• A. $\frac{3}{2}$Kt
• B. $\frac{kT}{2}$
• C. $\frac{3}{4}$kT
• D. kT

Answer 1

Answer: (B)

$\frac{kT}{2}$

Answer 2

ƒ= 1, E =$\frac{ƒ}{2}$ NkT =$\frac{kT}{2}$