Question

The average charge on each o atom and average bond order of I-O bond in $\text{I}{{\text{O}}_{6}}^{5-}$ is
(A) $-1$ and $1\cdot 67$
(B) $-5/6$ and $1\cdot 33$
(C) $-5/6$ and $1\cdot 67$
(D) $-5/6$ and $1\cdot 167$

Answer 1

Hint $\text{I}{{\text{O}}_{6}}^{5-}$: I is central atom where I surrounds by the six oxygen atom with negative charge. In this structure we have to calculate average charge and average bond order.
Average charge$=\dfrac{\text{Total charge of molecule}}{\text{No}\text{. of atom responsible for charge}}$
Bond order$=\dfrac{\text{Total bonds}}{\text{Total atom surrounding}}$

Complete step by step solution:
In$\text{I}{{\text{O}}_{6}}^{5-}$ the structure as follows

Charge on each oxygen atom=1
Total charge on molecule contributed by oxygen atom=$-5$
Average charge$=\dfrac{\text{Charge on molecule }}{\text{No}\text{. of total oxygen atom}}$
$\implies\dfrac{-5}{6}$
Average bond order:
No. of total bonds=7 [as one is double bond and 5 is single bond]
Total no. of oxygen
$\begin{aligned} &\implies \dfrac{7}{6} \\\ &\implies 1\cdot 16 \\\ \end{aligned}$

So the correct option is ‘D’

Note: Covalent bond: A bond which is formed by the shared pair of electrons is called covalent bond. Further covalent bond divided into two kinds.
Sigma Bond: A bond which is formed by overlapping of the internuclear axis is called sigma bond. It is of three kinds S-S overlapping, S-P overlapping, P-P overlapping.
Pi-Bond: A bond which is formed by the sideways overlapping of P-orbital is called pi-bond