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Question: The average age of a group of eight members is the same as it was \(3\) years ago when a young membe...

The average age of a group of eight members is the same as it was 33 years ago when a young member is substituted for an old member. The incoming member is younger to the outgoing member by
A)11A) 11 Years
B)24B) 24 Years
C)28C) 28 Years
D)16D) 16 Years

Explanation

Solution

In order to solve this type of problems related to age, we need to follow the following steps:
a)a) Express what we don’t know as a variable.
b)b) Create an equation based on the information provided.
c)c) Solve the unknown variable.
d)d) Substitute our answer back into the equitation to see if the left side of the equation equals the right side of the equation and hence, we will get our final result.

Complete step-by-step solution:
Let the average age of the eight members be x\overline x .
Let the ages be a1,a2,........a8{a_1},{a_2},........{a_8}
Therefore, we can write the average of eight members, x=a1+a2+.......+a88\overline x = \dfrac{{{a_1} + {a_2} + ....... + {a_8}}}{8}
By doing cross multiply, we get
a1+a2+.......+a8=8x\Rightarrow {a_1} + {a_2} + ....... + {a_8} = 8\overline x
We are just taking the a1{a_1} variable to the right hand side, we can write it as,
a2+........+a8=8xa1............(1)\Rightarrow {a_2} + ........ + {a_8} = 8\overline x - {a_1}............(1)
Let us consider the old member age is a1{a_1} and the young member age is a9{a_9}.
Also it stated as in the question those three years ago, the young member is substituted for old member.
Again it is stated as, average is same after substitution.
Therefore, x=(x93)+(a23)+........+(a83)8\overline x = \dfrac{{\left( {{x_9} - 3} \right) + ({a_2} - 3) + ........ + ({a_8} - 3)}}{8}
On solving, we can have,
a9+a2+........+a83(8)=8x\Rightarrow {a_9} + {a_2} + ........ + {a_8} - 3(8) = 8\overline x
By multiplying the numbers, we get
a9+a2+.......+a824=8x.....(2)\Rightarrow {a_9} + {a_2} + ....... + {a_8} - 24 = 8\overline x .....(2)
Substituting (1)(1) in (2)(2) we get,
a9+8xa124=8x\Rightarrow {a_9} + 8\overline x - {a_1} - 24 = 8\overline x
We can cancel the same terms on each side and take 24 - 24 to the right hand side.
Hence we get
a9a1=24\Rightarrow {a_9} - {a_1} = 24
Therefore, the incoming members are 2424 years younger to the outgoing member.

Thus the correct option is (B)(B) that is 2424.

Note: In order to solve age related problems, we need to know some important points to remember which are as follows:
i)i) If the present age is yy then nn times the present age ny.ny.
ii)ii) If the present age is xx, then the age nn years later we can write x+nx + n