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Question: The atomic number (Z) of an element whose k<sub>a</sub> wavelength is lis 11. The atomic number of a...

The atomic number (Z) of an element whose ka wavelength is lis 11. The atomic number of an element whos ka wavelength is 4l is equal to–

A

6

B

11

C

44

D

4

Answer

6

Explanation

Solution

l µ Ž λ1λ2\frac { \lambda _ { 1 } } { \lambda _ { 2 } } = (Z2−1Z1−1)2\left( \frac { Z _ { 2 } - 1 } { Z _ { 1 } - 1 } \right) ^ { 2 } =14\frac { 1 } { 4 }=122\frac { 1 } { 2 ^ { 2 } }

2(Z2 – 1) = Z1– 1

Z2 = 1 + = 1 + 11−12\frac { 11 - 1 } { 2 } = 6