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Question

Question: The atomic number of an element having the valency shell electronic configuration \(4s^{2}4p^{6}\) i...

The atomic number of an element having the valency shell electronic configuration 4s24p64s^{2}4p^{6} is

A

35

B

36

C

37

D

38

Answer

36

Explanation

Solution

Complete E.C.=[Ar]183d104s24p6.E.C. = \lbrack Ar\rbrack^{18}3d^{10}4s^{2}4p^{6}.

Hence no. of e=e^{-} = no. of protons=36=Z= 36 = Z.