Question
Physics Question on Nuclear physics
The atomic mass of 612C is 12.000000 u and that of 613C is 13.003354 u. The required energy to remove a neutron from 613C, if mass of neutron is 1.008665 u, will be :
A
62.5 MeV
B
6.25 MeV
C
4.95 MeV
D
49.5 MeV
Answer
4.95 MeV
Explanation
Solution
To remove a neutron from 613C, the nuclear reaction can be represented as:
613C→612C+neutron.
The mass defect Δm is given by:
Δm=(12.000000+1.008665)−13.003354=−0.00531u.
The energy required for this process is calculated using:
E=Δm×931.5MeV/u.
Substituting values:
E=0.00531×931.5≈4.95MeV.
The Correct answer is: 4.95 MeV