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Question: The asymptotes of the hyperbola \( xy - 3x + 4y + 2 = 0 \) are: A. \( x = - 4 \) B. \( x = 4 \)...

The asymptotes of the hyperbola xy3x+4y+2=0xy - 3x + 4y + 2 = 0 are:
A. x=4x = - 4
B. x=4x = 4
C. y=3y = - 3
D. y=3y = 3

Explanation

Solution

Hint : Take the general equation of the asymptote of the hyperbola and then compare the coefficients of the xx term and yy term in the equation of hyperbola for the asymptotes parallel to xx axis and yy axis.

Complete step-by-step answer :
The equation of the hyperbola is given by
xy3x+4y+2=0xy - 3x + 4y + 2 = 0 .
The equation of the hyperbola given in the question is
xy3x+4y+2=0xy - 3x + 4y + 2 = 0 .
For the asymptote of the hyperbola parallel to the xx axis , take the coefficient of the highest degree of xx in the equation to zero.
The equation of the hyperbola written in another form is
(y3)x+4y+2=0\left( {y - 3} \right)x + 4y + 2 = 0 .
The coefficient of the highest degree of xx in the equation is equal to y3y - 3 .
So, the equation of the asymptote parallel to xx -axis for the hyperbola
xy3x+4y+2=0xy - 3x + 4y + 2 = 0 is given by y3=0y - 3 = 0 or it can also be written as y=3y = 3 .
For the asymptote of the hyperbola parallel to the yy axis , take the coefficient of the highest degree of yy in the equation to zero.
The equation of the hyperbola written in another form is
(x+4)y3x+2=0\left( {x + 4} \right)y - 3x + 2 = 0 . The coefficient of the highest degree of yy in the equation is equal to x+4x + 4 .
So, the equation of the asymptote parallel to yy -axis for the hyperbola
xy3x+4y+2=0xy - 3x + 4y + 2 = 0 is given by x+4=0x + 4 = 0 or it can also be written as x=4x = - 4 .
So, the two asymptotes of the hyperbola xy3x+4y+2=0xy - 3x + 4y + 2 = 0 are x=4x = - 4 and y=3y = 3 .
So, the correct answer is “Option A and ”D.

Note : The equation of the asymptote parallel to the coordinate axis is given by equating the coefficient of the respective xx and yy variable of the highest degree in the equation of the hyperbola to zero.