Question
Question: The asymptotes of the hyperbola \(\frac{x^{2}}{a^{2}}\) – \(\frac{y^{2}}{b^{2}}\) = 1 make an angle ...
The asymptotes of the hyperbola a2x2 – b2y2 = 1 make an angle of 300 with x-axis then equation of diameter conjugate to the diameter y = 2x-
A
x – 2y = 0
B
3x – 2y = 0
C
x – 6y = 0
D
None of these
Answer
x – 6y = 0
Explanation
Solution
Slope of ax−by = 1 is ab = tan 30° Ž ab = 31
Slope of one diameter is m1 = 2
Two diameter are conjugate if m1m2 = a2b2
\ 2m2 = 1/3
Ž m2 = 1/6
Ž other diameter is y = 6x, x – 6y = 0.