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Question: The asymptotes of the hyperbola are 7x + 5y = 3 and 2x + 4y + 1 = 0. If it passes through (-2, 1) th...

The asymptotes of the hyperbola are 7x + 5y = 3 and 2x + 4y + 1 = 0. If it passes through (-2, 1) then its equation is

A

14x2 + 38xy +20y2 + x – 7y + 9 = 0

B

14x2 + 38xy +20y2 - x + 7y + 9 = 0

C

14x2 + 38xy +20y2 - 7x + y - 9 = 0

D

14x2 + 20y2 +38xy + x – 7y + 9 = 0

Answer

14x2 + 20y2 +38xy + x – 7y + 9 = 0

Explanation

Solution

Since equations of Hyperbola and Asymptotes differ by a constant. Let the equation of Hyperbola is

(7x + 5y- 3)(2x + 4y + 1) = λ

But it passes through (-2, 1) ⇒ λ = -12

∴ The equation of hyperbola is

14x2 + 20y2 +38xy + x – 7y + 9 = 0