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Question

Mathematics Question on Arithmetic Mean

The arithmetic mean and the harmonic mean between 2 numbers are 27 and 12 respectively, then their geometric mean is given by:

A

15

B

18

C

17

D

16

Answer

18

Explanation

Solution

Let's use the formulas for the arithmetic mean (AM), harmonic mean (HM), and geometric mean (GM) for two numbers a and b
1.(AM=a+b2)1. ( AM = \frac{a + b}{2} )
2.(HM=21a+1b)2. ( HM = \frac{2}{\frac{1}{a} + \frac{1}{b}} )
3.(GM=a×b)3. ( GM = \sqrt{a \times b} )

Given:
AM = 27
HM = 12

From the given AM:
(a+b2=27)( \frac{a + b}{2} = 27 )
(a+b=54).......(i)( a + b = 54 ) .......(i)

From the given HM:
21a+1b=12\frac{2}{\frac{1}{a} + \frac{1}{b}} = 12

2aba+b=12\frac{2ab}{a + b} = 12

2ab=12(a+b)2ab = 12(a + b)
2ab=12(54)2ab = 12(54)
2ab=6482ab = 648
[ab=324].......(ii)[ ab = 324 ] .......(ii)

Now, the geometric mean is
GM=a×bGM = \sqrt{a \times b}
GM=324GM = \sqrt{324}
GM=18GM = 18

So, the correct answer is B : 18.