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Question

Question: The area of triangle formed by the points \((a,b + c),\) \((b,c + a),\) \((c,a + b)\) is equal to....

The area of triangle formed by the points (a,b+c),(a,b + c), (b,c+a),(b,c + a), (c,a+b)(c,a + b) is equal to.

A

abcabc

B

a2+b2+c2a^{2} + b^{2} + c^{2}

C

ab+bc+caab + bc + ca

D

0

Answer

0

Explanation

Solution

Area of triangle =12ab+c1bc+a1ca+b1= \frac { 1 } { 2 } \left| \begin{array} { l l l } a & b + c & 1 \\ b & c + a & 1 \\ c & a + b & 1 \end{array} \right|

=12a+b+cb+c1b+c+ac+a1c+a+ba+b1= \frac { 1 } { 2 } \left| \begin{array} { l l l } a + b + c & b + c & 1 \\ b + c + a & c + a & 1 \\ c + a + b & a + b & 1 \end{array} \right|

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