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Question: The area of triangle \[ABC\] is equal to \[\left( {{a^2} + {b^2} - {c^2}} \right)\] where \[a\], \[b...

The area of triangle ABCABC is equal to (a2+b2c2)\left( {{a^2} + {b^2} - {c^2}} \right) where aa, bb and cc are the sides of triangle. Find the value of tanC\tan C.

Explanation

Solution

Here we need to find the tangent of angle of the triangle. We will first draw the triangle with their sides and angles and then we will use the formula of area triangle and then the formula of sine of angle of the triangle in terms of the area and then we will find the cosine of angle of the triangle in terms of the area and to get the tangent of angle of the triangle, we will take the ratio of both of them.

Formula used:
Δ=12absinC\Delta = \dfrac{1}{2}ab\sin C, where, aa and bb are the length of the sides of the triangle and Δ\Delta is the area of the triangle.

Complete step-by-step answer:
We will first draw the triangle ABCABC, aa, bb and cc are the sides of the triangle.

It is given that
Δ=(a2+b2c2)\Delta = \left( {{a^2} + {b^2} - {c^2}} \right) …………. (1)\left( 1 \right)
We know that the area of triangle in terms of sides and angle of the triangle is given by
Δ=12absinC\Rightarrow \Delta = \dfrac{1}{2}ab\sin C
On further simplification, we get
sinC=2Δab\Rightarrow \sin C = \dfrac{{2\Delta }}{{ab}} ………………… (2)\left( 2 \right)
And we also know that cosC=a2+b2c22ab\cos C = \dfrac{{{a^2} + {b^2} - {c^2}}}{{2ab}}.
On substituting equation (1)\left( 1 \right) in the above equation, we get
cosC=Δ2ab\Rightarrow \cos C = \dfrac{\Delta }{{2ab}} ……………. (3)\left( 3 \right)
Now, we will take the ratio of the equation (2)\left( 2 \right) and equation (3)\left( 3 \right). Therefore, we get
sinCcosC=2ΔabΔ2ab\dfrac{{\sin C}}{{\cos C}} = \dfrac{{\dfrac{{2\Delta }}{{ab}}}}{{\dfrac{\Delta }{{2ab}}}}
Using the trigonometric formula sinθcosθ=tanθ\dfrac{{\sin \theta }}{{\cos \theta }} = \tan \theta , we get
tanC=2ΔabΔ2ab\Rightarrow \tan C = \dfrac{{\dfrac{{2\Delta }}{{ab}}}}{{\dfrac{\Delta }{{2ab}}}}
On further simplifying the fraction of the right hand side of the equation.
tanC=2×2=4\Rightarrow \tan C = 2 \times 2 = 4
Hence, the value of tanC\tan C is equal to 4.

Note: A triangle is a two dimensional figure which has three sides. We have also used basic trigonometric identities to find different angles of the triangle. Trigonometric identities are defined as the equalities that contain the trigonometric function and also it is true for all the values of the variables.