Question

The area of the triangle inscribed in the parabola y² = 4x, whose vertices are given by t₁= ½ , t₂ = 1, t₃ = 2 is

• A. 7/2 sq.unit
• B. 5/2 sq.unit
• C. 3/2 sq.unit
• D. 3/4 sq.unit

Answer 1

Answer: (D)

3/4 sq.unit

Answer 2

Required Area = $\left| a^{2}(t_{1} - t_{2})(t_{2} - t_{3})(t_{3} - t_{1}) \right|$

= $\left| \mathbf{1.(1/2}\mathbf{-}\mathbf{1)(1}\mathbf{-}\mathbf{2)(2}\mathbf{-}\mathbf{1/2)} \right|$

= ¾