The area of the region (\left\\{(x,y):x^2≤y≤|x^2-4|,y≥1\righ... | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

The area of the region $\left\\{(x,y):x^2≤y≤|x^2-4|,y≥1\right\\}$ is

A

$\frac{4}{3}(4\sqrt2-1)$

B

$\frac{4}{3}(4\sqrt2+1)$

C

$\frac{3}{4}(4\sqrt2-1)$

D

$\frac{3}{4}(4\sqrt2+1)$

Answer

$\frac{4}{3}(4\sqrt2-1)$

Explanation

Solution

The correct answer is (A) : $\frac{4}{3}(4\sqrt2-1)$