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Question

Question: The area of the region bounded by the curve y =\(\frac { 1 } { 1 + ( \tan x ) ^ { 1 / 2 } }\) and th...

The area of the region bounded by the curve y =11+(tanx)1/2\frac { 1 } { 1 + ( \tan x ) ^ { 1 / 2 } } and the x-axis between the ordinates x = π/6 and x = π/3 is

A

π/4

B

π/2

C

π/8

D

None of these

Answer

None of these

Explanation

Solution

The given curve is y =11+(tanx)1/2\frac { 1 } { 1 + ( \tan x ) ^ { 1 / 2 } }

⇒ y =(cosx)1/2(sinx)1/2+(cosx)1/2\frac { ( \cos x ) ^ { 1 / 2 } } { ( \sin x ) ^ { 1 / 2 } + ( \cos x ) ^ { 1 / 2 } }

Area bounded between the intervals x = π/6

and x = π/3 is given by

A =dx

= dx

= dx

Adding 2A =

⇒ A = π12\frac { \pi } { 12 } sq. units