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Question: The area of the plane figure bounded by the interval [–5p/6, p] of the x-axis, the graph of the func...

The area of the plane figure bounded by the interval [–5p/6, p] of the x-axis, the graph of the function y = cos x and the segments of the straight lines x = –5p/6 and x = p is -

A

3/2

B

5/2

C

3/4

D

7/2

Answer

7/2

Explanation

Solution

Required area =5π/6πcosx\int _ { - 5 \pi / 6 } ^ { \pi } | \cos x | dx

= – 5π/6π/2cosxdx\int _ { - 5 \pi / 6 } ^ { - \pi / 2 } \cos x d x +π/2πcosxdx\int _ { \pi / 2 } ^ { \pi } \cos x d x= – sin + sin – sin = 7/2.