Question

The area of the figure bounded by y² = 9x and y = 3x is -

• A. 1
• B. ¼
• C. ½
• D. 2

Answer 1

Answer: (C)

½

Answer 2

Required area

= area OPQRO – area DOQR

= $\int _ { 0 } ^ { 1 } \sqrt { 9 x }$ dx – $\frac { 1 } { 2 }$ × 1 × 3 = 3 $\frac { 2 } { 3 }$ $\left. x ^ { 3 / 2 } \right| _ { 0 } ^ { 1 }$ – $\frac { 3 } { 2 }$ = $\frac { 1 } { 2 }$.