Question

The area of the figure bounded by the curves

y = |x – 1| and y = 3 – | x | is -

• A. 2
• B. 3
• C. 4
• D. None of these

Answer 1

Answer: (C)

4

Answer 2

Required area

= $\int _ { - 1 } ^ { 0 } 3$ + x – (–x + 1) dx + $\int _ { 0 } ^ { 1 } 3 - x - ( - x + 1 ) d x$+

$\int _ { 1 } ^ { 2 } 3 - x - ( x - 1 ) d x$ = $\int _ { - 1 } ^ { 0 } ( 2$ + 2x) dx + $\int _ { 0 } ^ { 1 } 2$dx + $\int _ { 1 } ^ { 2 } ( 4 - 2 x )$ dx

= 4 sq. units..