Question

The area of the figure bounded by the curves y = |x-1| and y=3-|x| is

• A. 2
• B. 3
• C. 4
• D. 1

Answer 1

Answer: (C)

4

Answer 2

Required area

$\int _ { - 1 } ^ { 0 } \{ ( 3 + x ) - ( - x + 1 ) \}$ $+ \int _ { - 1 } ^ { 0 } \{ ( 3 - x ) - ( - x + 1 ) \} d x + \int _ { 1 } ^ { 2 } \{ ( 3 - x ) - ( x - 1 ) \} d x$

= $0 - ( - 2 + 1 ) + ( 2 - 0 ) + ( 8 - 4 ) - ( 4 - 1 )$

$= 1 + 2 + 4 - 3 = 4$

(