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Question

Question: The area of the circle and the area of a regular polygon of n sides, and of perimeter equal to that ...

The area of the circle and the area of a regular polygon of n sides, and of perimeter equal to that of the circle are in the ratio of

A

tan(π3)\left( \frac { \pi } { 3 } \right): πn\frac { \pi } { \mathrm { n } }

B

cot : πn\frac { \pi } { \mathrm { n } }

C

sin: πn\frac { \pi } { \mathrm { n } }

D

cos : πn\frac { \pi } { \mathrm { n } }

Answer

tan(π3)\left( \frac { \pi } { 3 } \right): πn\frac { \pi } { \mathrm { n } }

Explanation

Solution

The perimeter of a regular polygon of n sides

= 2nr sin

If the radius of the circle is a then 2pa = 2nr sin ... (i)

Now area of polygon = n

̃ ratio of areas of circle and polygon

= =: (from (i)