Question

The area of smaller portion bounded by

|y| = – x + 1 and y² = 4x is -

• A. 1 sq unit
• B. 2 sq unit
• C. 3 sq unit
• D. None

Answer 1

Answer: (D)

None

Answer 2

Required area = 2 + DABS

= 2

= 2 $\left[ \frac { 4 } { 3 } ( 5 \sqrt { 2 } - 7 ) + 6 - 4 \sqrt { 2 } \right]$ Sq. units