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Question: The area of cross-section of a wire of length 1.1 metre is 1 mm<sup>2</sup>. It is loaded with 1 kg....

The area of cross-section of a wire of length 1.1 metre is 1 mm2. It is loaded with 1 kg. If Young's modulus of copper is 1.1×1011 N/m21.1 \times 10 ^ { 11 } \mathrm {~N} / \mathrm { m } ^ { 2 }, then the increase in length will be (If

A

0.01 mm

B

0.075 mm

C

0.1 mm

D
  1. 15 mm
Answer

0.1 mm

Explanation

Solution

l=mgLAY=1×10×1.11.1×1011×10−6m=0.1 mml = \frac { m g L } { A Y } = \frac { 1 \times 10 \times 1.1 } { 1.1 \times 10 ^ { 11 } \times 10 ^ { - 6 } } m = 0.1 \mathrm {~mm}