Question

The area of closed figure bounded by y = cos x, y = 1 + $\frac { 2 } { \pi }$ x and x = $\frac { \pi } { 2 }$ is

• A. $\frac { 3 \pi } { 4 }$
• B. $\frac { \pi } { 2 }$
• C. $\frac { 3 \pi - 4 } { 4 }$
• D. $\frac { \pi - 4 } { 4 }$

Answer 1

Answer: (C)

$\frac { 3 \pi - 4 } { 4 }$

Answer 2

Required area = $\int _ { 0 } ^ { \pi / 2 } \left( 1 + \frac { 2 } { \pi } x \right) - \cos x d x$