Question

The area (in sq. units) of the region enclosed between the parabola y2 = 2x and the line x + y = 4 is _______.

Answer 1

The correct answer is 18

Required Area :
$= \int_{-4}^{2} \left(4 - y - \frac{y^2}{2}\right) \,dy$
$=\left[4y - \frac{y^2}{2} - \frac{y^3}{6}\right]_{2}^{4}$
= 18 square units.