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Question

Mathematics Question on applications of integrals

The area (in s units) of the region \\{ (x , y) : x \geq 0 , x + y \leq 3, x^2 \leq 4 y and y \leq 1 + \sqrt{x} \\} is

A

32\frac{3}{2}

B

73\frac{7}{3}

C

52\frac{5}{2}

D

5912\frac{59}{12}

Answer

52\frac{5}{2}

Explanation

Solution

Area of shaded region
=01= \int\limits^{1}_{0} (x+1x24)dx+\left(\sqrt{x}+1-\frac{x^{2}}{4}\right)dx+ =12= \int\limits^{2}_{1} ((3x)x24)dx\left(\left(3-x\right)-\frac{x^{2}}{4}\right)dx
=52= \frac{5}{2 } s unit