Question
Mathematics Question on applications of integrals
The area (in s units) bounded by the curves y=x,2y−x+3=0,x-axis and lying in the first quadrant is
A
36
B
18
C
427
D
9
Answer
9
Explanation
Solution
Solving y=x with 2y−x+3=0, we have 2x−x+3=0⇒(x−3)(x+1)=0
∴x=1,9
Area =0∫3[(2y+3)−y2]dy
=y2+3y−3y3∣03
=9+9−9=9