The area enclosed by y 2 = 8 x and y = √2x that lies outside... | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

The area enclosed by y 2 = 8 x and y = √2x that lies outside the triangle formed by $y=√2x,x=1,y=2√2$ , is equal to

A

$\frac{16\sqrt2}{6}$

B

$\frac{11\sqrt2}{6}$

C

$\frac{13\sqrt2}{6}$

D

$\frac{5\sqrt2}{6}$

Answer

$\frac{13\sqrt2}{6}$

Explanation

Solution

The correct option is(C): $\frac{13\sqrt2}{6}$

The area enclosed by y2 = 8x and y = √2x that lies outside the triangle formed by

$=\frac{\sqrt2}{6}(48-32-3)=\frac{13\sqrt2}{6}$