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Question: The area bounded by y<sup>2</sup> = –4x, and its latus-rectum is...

The area bounded by y2 = –4x, and its latus-rectum is

A

Not defined

B

1 sq. union

C

2/3 sq. union

D

None of these

Answer

None of these

Explanation

Solution

The required area = ∣−2∫−10−4xdx∣\left| - 2 \int _ { - 1 } ^ { 0 } \sqrt { - 4 x } d x \right|

=

= ∣ 13[0−(4)3/2]\left\lvert \, \frac { 1 } { 3 } \left[ 0 - ( 4 ) ^ { 3 / 2 } \right] \right. = 83\frac { 8 } { 3 }