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Question

Mathematics Question on Integrals of Some Particular Functions

The area bounded by the curve y=sinxy = \sin x, xx-axis and the ordinates x=0x = 0 and x=π/2x = \pi /2 is

A

π\pi

B

π/2\pi/2

C

1

D

2

Answer

1

Explanation

Solution

Area =0π/2ydx= \int\limits^{\pi/2}_{0} y\, dx
=0π/2sinxdx= \int\limits^{\pi/2}_{0} \sin x \,dx
=[cosx]0π/2=1= \left[-\cos x\right]^{\pi/2}_{0} = 1