Question

The area bounded by the curve $x = 3y^{2} - 9$ and the line $x = 0$, $y = 0$ and $y = 1$ is

• A. $8$ s units
• B. $8/3$ s units
• C. $3/8$ s units
• D. $3$ s units

Answer 1

Answer: (A)

$8$ s units

Answer 2

We have, $x=3y^{2}-9 \,\Rightarrow\quad3y^{2}=x+9$ Required area = area of shaded region $A=\left|\int\limits_{0}^{1}\left(3y^{2}-9\right)dy\right|=\left|y^{3}-9y\right|_{0}^{1}=\left|1-9\right|=8$ s units