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Question: The area between the parabola y<sup>2</sup> = 4ax and its latus rectum is –...

The area between the parabola y2 = 4ax and its latus rectum is –

A

(8/3)a

B

(8/3)a2

C

(4/3)a

D

2/3 unit

Answer

(8/3)a2

Explanation

Solution

Area = 20aydx=20a4axdx2 \int _ { 0 } ^ { a } y d x = 2 \int _ { 0 } ^ { a } \sqrt { 4 a x } d x

2×2a×23x3/20a=83a22 \times 2 \sqrt { a } \times \frac { 2 } { 3 } \left| x ^ { 3 / 2 } \right| _ { 0 } ^ { a } = \frac { 8 } { 3 } a ^ { 2 }