Question

The area between the curve $y = \sin ^ { 2 } x$ $x -$ axis and the ordinates $x = 0$ and $x = \frac { \pi } { 2 }$ is

• A. $\frac { \pi } { 2 }$
• B. $\frac { \pi } { 4 }$
• C. $\frac { \pi } { 8 }$
• D. $\pi$

Answer 1

Answer: (B)

$\frac { \pi } { 4 }$

Answer 2

Required area

$= \frac { 1 } { 2 } [ x ] _ { 0 } ^ { \pi / 2 } - \frac { 1 } { 4 } [ \sin 2 x ] _ { 0 } ^ { \pi / 2 } = \frac { \pi } { 4 }$.