Question

The approximate wavelength of a photon of energy 2.48 eV is.

• A. 500 Å
• B. 5000 Å
• C. 2000 Å
• D. 1000 Å

Answer 1

Answer: (B)

5000 Å

Answer 2

By using $E ( e V ) = \frac { 12375 } { \lambda ( \AA ) }$

$\Rightarrow \lambda = \frac { 12375 } { 2.48 } = 4989.9 \AA \approx 5000 \AA$