Question

The approximate value of $\sin \, 31^{\circ}$ is

• A.

  0.5

• B.

  0.6

• C. < 0.5
• D. < 0.4

Answer 1

Answer: (A)

0.5

Answer 2

We know that, $\sin\, 30^{\circ}=\frac{1}{2}=0.5$
$\ln 1^{\text {st }}$ quadrant $\sin \, x$ is increasing function
$\therefore \sin \, 31^{\circ}>\sin \, 30^{\circ}$
$\Rightarrow \sin \, 31^{\circ}>0.5$