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Question: The apparent depth of needle lying a the bottom of the tank, which is filled with water of refractiv...

The apparent depth of needle lying a the bottom of the tank, which is filled with water of refractive index 1.33 to a height of 12.5cm is measured by a microscope to be 9.4cm. If water is replaced by a liquid of refractive index 1.63 upto the same height. What distance would the microscope have to be moved to focus on the needle again?

A

1.73 cm

B

2.13 cm

C

1.5 cm

D

2.9 cm

Answer

1.73 cm

Explanation

Solution

: Apparent depth

Here, Real depth= 12.5 cm and

=12.51.63=7.67 cm= \frac { 12.5 } { 1.63 } = 7.67 \mathrm {~cm}

Now the microscope will have to shift from its initial position to focus 7.67 cm depth object.

Shift distance =9.4−7.67=1.73 cm= 9.4 - 7.67 = 1.73 \mathrm {~cm}