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Question

Physics Question on Ray optics and optical instruments

The aperture of the objective is 24.4 cm. The resolving power of this telescope, if a light of wavelength 2440 Å is used to see the object will be:

A

8.1 × 106

B

10.0 × 107

C

8.2 × 105

D

1.0 × 10-8

Answer

8.2 × 105

Explanation

Solution

The correct answer is (C) : 8.2 × 105
R.P.=11.22λ/aR.P. = \frac{1}{1.22λ/a}
=24.4×10−21.22×2440×10−10=\frac{24.4 × 10-^{2}}{1.22 × 2440 × 10^{-10}}
=8.2×105= 8.2 × 10^{5}