Question

The anions (1) form hexagonal closest packing and the cations(3) occupy only 2/3 of octahedral holes. The simplest formula of the ionic compound is –

• A. CA
• B. C3A2
• C. C4A3
• D. C2A3

Answer 1

Answer: (D)

C2A3

Answer 2

The no. of A in one unit cell = 6

The no. of C in one unit cell = $\frac{2}{3}$× 6 = 4

\ m.f is C₄A₆ º C₂A₃