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Chemistry Question on Electronic Configurations Of Elements And The Periodic Table

The anion O−O^- is isoelectronic with

A

N2−N^{2-}

B

F−F^-

C

N3−N^{3-}

D

NeNe

Answer

N2−N^{2-}

Explanation

Solution

The anion Oˉ(8+1=9\bar{O}(8 + 1 = 9 electrons) is isoelectronic with N2−(7+2=9N^{2-} (7 + 2 = 9 electrons). Isoelectronic species have same number of electrons. (N3−=7+3=10e−(N^{3-} = 7 + 3 = 10e^-,
F−=9+1=10e−F^- = 9 + 1 = 10e^- and Ne=10e−)Ne = 10e^-).