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Question

Physics Question on single slit diffraction

The angular width of the central maximum of the diffraction pattern in a single slit of width a experiment, with λ\lambda as the wavelength of light, is

A

3λ2a\frac{3\lambda }{2a}

B

λ2a\frac{\lambda }{2a}

C

2λa\frac{2\lambda }{a}

D

λa\frac{\lambda }{a}

Answer

2λa\frac{2\lambda }{a}

Explanation

Solution

The central maxima lies between the first minima on both sides.
The angular width of central maxima
=2θ=2λa=2 \theta=\frac{2 \lambda}{a}.